Suppose that 3 j of work is needed to stretch a spring from its natural length of 36 cm to a length of 46 cm. (a) how much work is needed to stretch the spring from 40 cm to 42 cm? (round your answer to two decimal places.) 0.12 incorrect: your answer is incorrect. j (b) how far beyond its natural length will a force of 25 n keep the spring stretched? (round your answer one decimal place.) cm

a) 0.24 J

b) 2.1 cm

Explanation:

The work needed to stretch a spring is given by:

where x is the elongation:

We need to know the spring constant so we can calculate what is asked in question a.

so:

For b:

According to Hooke's law:

A force of 25N is pulling on the spring, so the spring pulls back with the same magnitude but in the opposite direction.

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