The beryllium isotope 4be is unstable and decays into two α particles (helium nuclei of mass 6.68 × 10^−27 kg) with the release of 1.5 × 10^−14 j of energy. determine the velocities of the two α particles that arise from the decay of a 4be nucleus at rest, assuming that all the energy appears as kinetic energy of the particles. answer in units of m/s.

v=1.56 x 10⁶ m/s

Explanation:

Given that

Mass alpha ,m=6.68 x 10⁻²⁷ kg

4Be is unstable

4Be  → 2α   + 1.5 × 10⁻¹⁴ J

Lets take speed of α particle is v m/s

So from energy conservation

Here

E= 1.5 × 10⁻¹⁴ J

m=6.68 x 10⁻²⁷ kg

1.5 × 10⁻¹⁴  = 6.68 x 10⁻²⁷ x v²

v²= 0.224 x 10¹³

v=1.56 x 10⁶ m/s

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

explanation:

wheres the pic