Amachine carries a 4.0 kg package from an initial position of di = (0.50 m) + (0.75 m) + (0.20 m) at t = 0 to a final position of df = (7.20 m) + (13.0 m) + (7.30 m) at t = 11 s. the constant force applied by the machine on the package is f = (2.00 n) + (4.00 n) + (6.00 n) . (a) for that displacement, find the work done on the package by the machine's force. j (b) also, find the power of the machine's force on the package. w

a)

b)

Explanation:

The work is defined as:

when the force is on the same direction of the movement.

We need to calculate the displacement in each direction, so:

now having the displacement, we can calculate the work done by the machine:

The total work is the sum of each of them:

and the power is given by:

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explanation: