Aship maneuvers to within 2.46×10³ m of an island’s 1.80 × 10³ m high mountain peak and fires a projectile at an enemy ship 6.10 × 10² m on the other side of the peak, as illustrated. the ship shoots the projectile with an initial velocity of 2.55×10² m/s at an angle of 74.9°.how close to the enemyship does the projectile land? how close (vertically) does the projectile come to the peak?

The distance close to the peak is 597.4 m.

Explanation:

Given that,

Distance of the first ship from the mountain

Height of island

Distance of the enemy ship from the mountain

Initial velocity

Angle = 74.9°

We need to calculate the horizontal component of initial velocity

Using formula of horizontal component

Put the value into the formula

We need to calculate the vertical component of initial velocity

Using formula of vertical component

Put the value into the formula

We need to calculate the time

Using formula of time

We need to calculate the height of the shell on reaching the mountain

Using equation of motion

Put the value in the equation

We need to calculate the distance close to the peak

Using formula of distance

Put the value into the formula

Hence, The distance close to the peak is 597.4 m.

v 154.9= 0.9 length length s little over 154.9cm