The magnetic field of an electromagnetic wave is given by b(x, t)=(0.1μt)sin[(6π×106m−1)x−(1.80π×1 015s−1)t]

1) calculate the amplitude of the electric field.
2) calculate the speed of the wave.
3)calculate the frequency of the wave.
4) calculate the period of the wave.
5) calculate the wavelength

Given that

B(x,t)=(0.1μT)sin[(6π×10⁶ m⁻¹)x−(1.80π×10¹⁵ s⁻¹)t]

We know that standard form of a wave equation given as'

y= A sin ( kx - ωt)

k=6π×10⁶

We know that

2π/λ= k

2π = 6π×10⁶ x λ  ⇒ λ= 3.33 x 10⁻⁷ m

ω=1.80π×10¹⁵

We know that

ω=2π f

f= 1.80π×10¹⁵ /2π = 0.9 ×10¹⁵ Hz

1)

Amplitude of e electric field Eo= C Bo

Eo= C Bo

Bo=0.1μ

C=3 x 10⁸ m/s

Eo= C Bo = 3 x 10⁸ x 0.1 x 10⁻⁶

Eo= 30 N/C

2)

Speed of the wave = 3 x 10⁸ m/s

3)

 f=0.9 ×10¹⁵ Hz

4)

T=1/f

T=1.15 x 10⁻¹⁵ s

5)

λ= 3.33 x 10⁻⁷ m

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.