Imagine a gene pool in a random-mating population. the frequency of allele b1 is 0.4; the frequency of allele b2 is 0.6. what is the predicted frequency of heterozygotes among the offspring?

0.48

Explanation:

Given that

Frequency b1=0.4

Frequency b2=0.6

The predicted frequency of heterozygotes is given as

f(b1b2)= 2 b1 x b2

Now by putting the values

f(b1b2)= 2 b1 x b2

f(b1b2)= 2 x 0.4 x 0.6

f(b1b2)=0.48

So the answer is 0.48.

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