If a projectile was launched at an angle of 13 degrees above the ground and hit its target 14.3 m away, what was the projectile's launch speed? ignore air resistance and acceleration due to gravity is 9.8m/s^2.

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

the answer is a 3.8cm

explanation: