In the steady state 1.2 ✕ 1018 electrons per second enter bulb 1. there are 6.3 ✕ 1028 mobile electrons per cubic meter in tungsten. the cross-sectional area of the tungsten filament in bulb 1 is 1.3 ✕ 10-8 m2. the electron mobility in hot tungsten is 1.2 ✕ 10-4 (m/s)/(n/c). calculate the magnitude of the electric field inside the tungsten filament in bulb 3.

E=12.2V/m

Explanation:

To solve this problem we must address the concepts of drift velocity. A drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field.

The equation is given by,

Where,

V= Drift Velocity

I= Flow of current

n= number of electrons

q = charge of electron

A = cross-section area.

For this problem we know that there is a rate of 1.8*10^{18} electrons per second, that is

Mobility

We can find the drift velocity replacing,

The electric field is given by,

the device is called “ rocket engine”

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xd