A2000 kg car is driving on a flat road around a turn with a 50 meter radius of curvature. when the road is dry, the car can go around the turn at a maximum speed of 20 m/s without slipping. what is the coefficient of friction between the road and the tires? is this the coefficient for static or kinetic friction?

μ =0.8

This is the  coefficient for  kinetic friction

Explanation:

Given that

m = 2000 kg

r= 50 m

v= 20 m/s

When a car moves around a circular arc the it experience a radial force F

F= m v²/r

To avoid the slipping friction force must be equal to F

Friction force Fr= μ m g

Fr= F

μ m g= m v²/r

μ =  v²/rg

By putting the values

   ( take g =10 m/s²)

μ =0.8

This is the  coefficient for  kinetic friction

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day