Arectangular loop of wire carrying a 4.0-a current is placed in a magnetic field of 0.60 t. the magnitude of the torque acting on this wire when the plane of the loop makes a 30° angle with the field is measured to be 1.1 n · m. what is the area of this loop?
a) 0.20 m2
b) 0.53 m2
c) 0.26 m2
d) 0.80 m2
e) 0.40 m2

b)A= 0.52 m²

Explanation:

Given that

I= 4 A

B= 0.6 T

θ=90° - 30° = 60°

T= 1.1 N.m

We know that torque T given as

T= I B A sinθ

Now by putting the values

T= I B A sinθ

1.1= 4 x 0.6 x A x  sin 60°

A= 0.52 m²

answer: what are you talking about?

explanation:

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2