Calculate the wavelength of light that has its second-order maximum at 45.0º when falling on a diffraction grating that has 5000 lines per centimeter. note: if there are 5,000 lines per cm, then the distance between lines (our value for d) is cm/5,000.

Here, the wavelength of the light λ, that has a its 2nd order maximum m=2, at θ = 45.0º, when falling on a grating with 5000 lines per centimeter, can be calculated using the principle of diffraction grating which states that:

(See the attached illustration picture)

Explanation:

Where;

d=distance between lines =  (Given in the question)

m = order of the maximum = 2

θ=angle of diffraction of the light = 45.0º

and

λ = wavelength of the light = Unknown?

Now, we can do the calculation as follows,

Hence, the wavelength of light that has its second-order maximum at 45.0º when falling on a diffraction grating that has 5000 lines per centimeter is 0.0000707cm

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

b.

explanation:

10.0