Atextbook of mass 2.09 kg rests on a frictionless, horizontal surface. a cord attached to the book passes over a pulley whose diameter is 0.190 m, to a hanging book with mass 3.08 kg. the system is released from rest, and the books are observed to move a distance 1.26 m over a time interval of 0.800 s.

The tension in the part of the cord attached to the textbook is 6.58 N.

Explanation:

Given that,

Mass of textbook = 2.09 kg

Diameter = 0.190 m

Mass of hanging book = 3.08 kg

Distance = 1.26 m

Time interval = 0.800 s

Suppose,we need to calculate the tension in the part of the cord attached to the textbook

We need to calculate the acceleration

Using equation of motion

Put the value into the formula

We need to calculate the tension

When the book is moving with acceleration

Using formula of tension

Hence, The tension in the part of the cord attached to the textbook is 6.58 N.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .