A0.22lr caliber bullet has a mass of 38 grains (2.50 g) and a muzzle velocity of 1260 ft/s (380 m/s). the bullet is fired into a door made of a double thickness of pine boards, each with a thickness of 0.75 in. the average stopping force exerted by the wood is 960 n. how fast (in m/s) would the bullet be traveling after it penetrated through the door?

Explanation:

mass of the bullet,

muzzle velocity,

total thickness of the board on which the target is taken,

average stopping force by the board,

We know,

This "a" is the deceleration of bullet in the board material.

Now using the equation of motion,

-ve sign, because a is deceleration

is the velocity when it exits the board material.

the answer would be 32*f