Asprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash .
a ) how far does the sprinter travel during the first 6 seconds ?
b ) how much farther does the sprinter have to travel to reach the finish line ?

a) 36 m

b) 64 m

Explanation:

Given:

v₀ = 0 m/2

v = 12 m/s

t = 6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (12 m/s + 0 m/s) (6 s)

Δx = 36 m

The track is 100 m, so the sprinter still has to run another 64 m.

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