An irregularly-shaped object of length 9.2 m is placed with each end on a scale. if the scale on the right reads 73 n and the one on the left reads 91 n , how far from the left is the object's center of gravity?

5.1 m

Explanation:

from the question we are given the following:

length of the object (L) = 9.2 m

weight on the right scale (Wr) = 73 N

weight on the left scale (Wl) = 91 N

position of the center of gravity (CG) from the left = ?

We can get the position of the center of gravity (CG) by finding the net torque about the center of gravity (CG).

Take note of the following:

therefore taking the clockwise direction as positive the equation for the net torque about the center of gravity (CG) will be

(Wr x P) - (Wl x (9.2 - P)) = 0

(Wr x P) = (Wl x (9.2 - P))

P =

P =

P= 4.1 m

Recall that the distance of the center of gravity (CG) from the left end is the total length - P = 9.2 - P

= 9.2 - 4.1 = 5.1 m

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

i guess that visual aids present persuasive examples to what you are presenting, some factors would be theme (does it fit with the color, information, what you are presenting), size (can you see it, is it a big enough span of data/information), and overall look of the visual aid.

hope this : )