Look at the graph above. given that speed= change in distance / change in time, calculate the speed of the object. show your work

20 m/s

Explanation:

Your graph is linear, that means it is trying to say that the object moves exact same amount of distance ( 20 m ) in a unit time ( 1 s ).

That means the speed of the object does not change with time.

Y-axis shows the distance the object traveled and X-axis the time taken.

So as your suggest in your equation, try to find the distance the object moved ( 100 m )  in the given time period ( 5 s )

To find a change you should always subtract final value from initial value,

speed = change in distance / change in time

           =

           =  

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.