Aloaded truck with a mass of 3 tonnes traveling north at 60 km/h collides with a 1 tonne mass truck, traveling east at 90 km/h at a junction. calculate in which direction and how far the car is dragged by the truck, knowing that the coefficient of kinetic friction at the accident site is 0.5.

deg

m

Explanation:

= mass of the heavier truck = 3 tonnes

= velocity of truck before collision = kmh⁻¹

= mass of lighter truck = 1 tonne

= velocity of lighter truck before collision = kmh⁻¹

= velocity of combination after collision

Using conservation of momentum

magnitude of the final speed is given as

km/h

Direction is given as

deg

= velocity of combination after collision = 50.31 km/h = 13.98 m/s

= velocity of combination after it comes to stop = 0 m/s

= acceleration = =  -  = - 4.9 m/s²

= stopping distance

using the equation

m

the answer is false

explanation: