Athlete swims the length of 50m pool in 20sec and moves the return trip to the starting position in 22 sec. find the average velocity and speed . a) in the first half of the swim b) in the second half of the swim c) in the total trip. me pls i need

Explanation:

Average velocity is displacement over time.

Average speed is distance over time.

a) In the first half of the race, the displacement is 50m, and the distance is also 50m.

v = 50m / 20s = 2.5 m/s

s = 50m / 20s = 2.5 m/s

b) In the second half of the race, the displacement is -50m.  The distance is 50m.

v = -50m / 22s = -2.27 m/s

s = 50m / 22s = 2.27 m/s

c) In the total trip, the displacement is 0m.  The distance is 100m.

v = 0m / 42s = 0 m/s

s = 100m / 42s = 2.38 m/s

it may be wrong but i think its a

multiply 2kg by latent heat of vap