You and your brother are pushing a car with dead battery with forces of 20n and 25 n in the same direction what is the net force applied on the car

The net force, F = 45 N

Explanation:

Given,

I applied a force on the car, F₁ = 20 N

My brother applied a  force on the car, F₂ = 25 N

Neglecting the frictional force of the car

The two forces act in the same direction, so the magnitude of the resultant force is equal to the algebraic sum of the individual forces. The direction of the resultant force is along the line of the original force.

The net force is given by the formula,

                                          F = F₁ + F₂

Substituting the given values in the above equation,

                                          F = 20 N + 25 N

                                             = 45 N

Hence, the resultant force applied to the car is, F = 45 N

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j