Aperson is standing on a level floor. his head, upper torso, arms, and hands together weigh 458 n and have a center of gravity that is 1.31 m above the floor. his upper legs weigh 101 n and have a center of gravity that is 0.785 m above the floor. finally, his lower legs and feet together weigh 88.8 n and have a center of gravity that is 0.215 m above the floor. relative to the floor, find the location of the center of gravity for the entire body.

1.07804 m

Explanation:

W = Weight of upper body = 458 N

= Location of upper body = 1.31 m

W' = Weight of upper legs = 101 N

= Location of legs = 0.785 m

W'' = Weight of lower legs = 88.8 N

= Location of lower legs = 0.215 m

The center of gravity is the concentrated point of a body. It is given by

The center of gravity of the person is 1.07804 m from the floor.

gravitational energy

electrical energy

kinetic energy

ligh energy

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.