The 9.6 n weight is in equilibrium under the influence of the three forces acting on it. the f force acts from above on the left at an angle of α with the horizontal. the 6.9 n force acts from above on the right at an angle of 52◦ with the horizontal. the force 9.6 n acts straight down. what is the magnitude of the force f?

F= 5.95 N

Explanation:

Forces acting on the body  in equilibrium :

W = 9.6 N : in direcction vertical downward

F₁ = 6.9 N : acts from above on the right at an angle of 52° with the horizontal

F : acts from above on the left at an angle of α

x-y components of the force = 6.9 N

F₁x= 6.9 N*cos (52)°= 4.248 N

F₁y= 6.9N*sin (52)°= 5.437 N

Newton's first law for equilibrium

∑Fx=0

F₁x-Fx=0

Fx = F₁x

Fx = 4.248 N

∑Fy=0

F₁y + Fy -W = 0

Fy = W - F₁y

Fy = 9.6 N -  5.437 N

Fy = 4.16 N

Magnitude of the force F

F= 5.95 N