Bird bones have air pockets in them to reduce their weight. this also gives them an average density significantly less than that of the bones of other animals. suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 47 g and its apparent mass when submerged is 3.4 g (the bone is watertight).a. what mass of water is displaced?
b. what is the volume of the bone?
c. what is its average density?

a) 43.6g b)0.0000436m^3( 43.6cm^3) c)1078kg/m^3

Explanation:

Mass of the bone in air = 47g = 47/1000= 0.047kg

Apparent mass of the bone in water = 3.4g

Mass of water displaced = 47g - 3.4g, from upthrust which is the upward force acting upward on the body.

Mass of water displaced = 43.6g

Volume of the bone = volume of the water displaced

Density of water (1000kg/m^3) = mass of water displaced/ volume of water

Volume of water displaced = mass of water displaced/ density = 0.0436 in kg/1000 = 0.0000436m^3 ( 43.6cm^3)

Average density of the bone = total mass/ total volume = 0.047kg/ 0.0000436m^3 = 1078kg/m^3

6/12=1/2

step-by-step explanation:

a, c, d, e are all applying about success strategies.