A0.1-kg steel ball is dropped straight down onto a hard horizontal floor and bounces straight up. its speed just before and just after impact with the floor is 10 m/s. determine the magnitude of the impulse delivered to the floor by the steel ball. a) zero n • s b) 1 n • s c) 2 n • s d) 10 n • s e) 100 n • s

Impulse,

Explanation:

Given that,

Mass of the steel ball, m = 0.1 kg

Initial speed of the ball, u = -10 m/s (it straight down)

Final speed of the ball, v = +10 m/s (it straight up)

To find,

The magnitude of the impulse delivered to the floor by the steel ball.

Solution,

Let J is the magnitude of impulse. The change in momentum of an object to another is equal to the impulse delivered. Mathematically, it i given by :

J = 2 N.s

Therefore, the magnitude of the impulse delivered to the floor by the steel ball is 2 N.s. Hence, this is the required solution.

hey , the answer is c

. west