you are on the roof of a building, 46.0 m above the ground. your friend, who is 1.80 m tall, is standing next to the building. what speed would an egg dropped from rest be traveling when it hit your friend on the top of his head?

29.448

Explanation:

first determine the distance from the top of the roof to the friends head.

Since he is 1.80 min height ,

distance =  46.0-1.80

              = 44.2 m

egg is dropped from rest means that its starting velocity is zero. It has to travel 44.2 m subjected to the gravitational acceleration

Applying  Motion equation

where v= end velocity (speed)

           u=Starting velocity

           a= acceleration

           s= Distance

(Let gravitational acceleration assumed as

The speed of egg is 14.73 m/s

Explanation:

Given the height of building (H) = 46 m

The height of friend (h) = 1.8 m

Distance for the egg to travel (s) = H – h = 46 – 1.8 = 44.2 m

Applying second equation of motion,

u = 0 (as the egg is starting from the rest)

g = 9.81 (as the object is falling)

Substituting the values,

44.2=0+

= 9

t = 3 sec

Calculating speed,

Speed =  

Speed =

Therefore, the speed of egg is 14.73 m/s

powerful computers now, not then

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.