Acertain dielectric, with a dielectric constant 26, can withstand an electric field of 5 × 107 v/m. suppose we want to use this dielectric to construct a 0.3 µf capacitor that can withstand a potential difference of 2000 v. the permittivity of free space is 8.85 × 10−12 c 2 /n · m2 . (a) what is the minimum plate separation? (b) what must the area of the plates be?

 a) 40 µm b) 0.05 m2  

Explanation:

Assuming that the capacitor that we want to construct is of parallel plates type, we know that the Capacitance of this capacitor can be found using the following equation:

C= ε0 εr A / d

Now, we know that the dielectric, can withstand an electric field of 5 x 107 V/m, and between the plates of a capacitor, the electric field (which is constant for a given charge on the plates), and the voltaje between plates, are related by the following expression:

V = E. d, so, if the voltage between plates would be of 2000 V, and Emax can be of  

5 x 107 V/m, we can find the mimimum d between plates, as follows:

dmin = V/ Emax = 2000 V / 5 x 107 V/m = 40 µm

Replacing this value in (1) above:

C= 8.85 × 10−12 C 2 /N · m2. 26. A / 40 µm

Solving for A, we have the following:

A = 0.3 µF.40 µm / 8.85 × 10−12 C 2 /N · m2. 26 = 0.05 m2

Explanation:

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

there are no correct statementd on the list of choices you provided.