How much work is done in lifting an object that has a mass of 5kg a vertical distance of 2m?

100 Joules

The question is testing on how to calculate work done;

We are given;

We are required to calculate the amount of work done.

How do we calculate work done?

In this case;

Force = mass × 10 N/kg

         = 5 kg × 10 N/kg

         = 50 N

Therefore;

work done = 50 N × 2 m

                  = 100 Joules

Thus, the work done in lifting the object is 100 Joules

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!