Question 11 of 11 | page 11 of 11
question 11 (1 point)
cygnus x-1 is orbiting the massive star hde226868, with a period of 5.6 days. if the gravitational force acting
between them was greater, how would that affect the period?

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

                                        v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

                                         ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

                                     T = 2π/ω

By substitution,

                                      T = 2π(R +h)√[(R + h)/GM]

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.

so easy. just google the electromagnetic waves and it’ll pop up.