Abat strikes a 0.145-kg baseball. just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leaves the bat traveling to the left at an angle of 30 ∘ above horizontal with a speed of 65.0 m/s . the ball and bat are in contact for 1.75 ms .

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball,

Time of contact,

(a) It is assumed to find the horizontal component of average force. It is given by :

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//