Aheavy boy and a lightweight girl are balanced on a mass-less seesaw. if they both move forward so that they are one-half their original distance from the pivot point, what will happen to the seesaw? assume that both people are small enough compared to the length of the seesaw to be thought of as point masses. a. it is impossible to say without knowing the masses.
b. it is impossible to say without knowing the distances.
c. the side the boy is sitting on will tilt downward.
d. nothing will happen; the seesaw will still be balanced.
e. the side the girl is sitting on will tilt downward.

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

D. Nothing will happen; the seesaw will still be balanced

Explanation: According to the principles of moment which states that for a body to be at equilibrium, the sum of clockwise moments must be equal to the sum of anticlockwise moments.

if the mass-less seesaw was initially balanced at a particular distance, it will still be balanced if the boy and the girl move forward to cover half their initial distances from the pivot.

D perfectly depicts the outcome.

the answer is b, have negligible mass

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.