A100 kg box is suspended from two ropes. the "left rope makes an angle of 20" degrees with the vertical, and the right rope makes an angle of 40 degrees. what is the tension (in newtons) on the right rope?

Explanation:

It is given that,

Mass of the box, m = 100 kg          

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.  

From the attached figure, the x and y component of forces is given by :

Let and is the resultant in x and y direction.

As the system is balanced the net force acting on it is 0. So,

.............(1)

..................(2)

On solving equation (1) and (2) we get:  

(tension on the left rope)

(tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.                            

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