The kinetic energy of an object attached to a horizontal ideal spring is denoted by ke and the elastic potential energy by pe. for the simple harmonic motion of this object the maximum kinetic energy and the maximum elastic potential energy during an oscillation cycle are kemax and pemax, respectively. in the absence of friction, air resistance, and any other nonconservative forces, which of the following equations applies to the object-spring system? a. ke + pe = constant b. kemax = pemax

Both A and B

Explanation:

Given that

Kinetic energy = KE

Potential energy = PE

For simple harmonic motion

The maximum kinetic energy occurs at the mean position but on the other hand maximum potential energy occurs at the extreme positions .But from the energy conservation ( if there is no any resistance force)

1.

Maximum  kinetic energy = Maximum potential energy

KE(max) = PE(max)

2.

kinetic energy + potential energy = Constant

KE + PE = C

So both the option is correct.

answer; i believe the correct answer is (40,000 j) good luck