You want to wind a solenoid that is 3.5 cm in diameter, is 23 cm long, and will have a magnetic field of 0.0250 t when a current of 3.0 a is in the wire that makes up the solenoid. 1) what total length of wire do you need?

L'=167.7 m

Explanation:

Given that

d= 3.5 cm

L= 23 cm

B=0.025 T

I= 3 A

As we know that magnetic field in solenoid given as

N=Number of turns

L=Length

B=Magnetic filed

I=Current

Now by putting the all values

N=1525.23 turns = 1526 turns

Total length L'=Nπd

L'=1526 x 3.14 x 0.035

L'=167.7 m

b.

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