Somewhere in the vast flat tundra of planet tehar, a projectile is launched from the ground at an angle of 60 degrees. it reaches the maximum height of 15 m. the acceleration due to gravity is 30 m/s2. find the horizontal range of the projectile in meters.

R = 0.0503 m

Explanation:

This is a projectile launching exercise, to find the range we can use the equation

       R = v₀² sin 2θ / g

How we know the maximum height

      ² =² - 2 g y

      = 0

      = √ 2 g y

      = √ 2 9.8 / 15

      = 1.14 m / s

Let's use trigonometry to find the speed

    sin θ = / vo

    vo = / sin θ

    vo = 1.14 / sin 60

    vo = 1.32 m / s

We calculate the range with the first equation

     R = 1.32² sin(2 60) / 30

    R = 0.0503 m

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.