Aspring stretches 5.52 cm vertically when a 2.50 kg object is suspended from it. find the distance (in cm) the spring stretches if you replace the 2.50 kg object with a 3.40 kg object. assume that the spring obeys the hook's law.

7.51 cm

Explanation:

y1 = 5.52 cm

m1 = 2.5 kg

m2 = 3.4 kg

Let the spring stretches by the distance y2.

According to Hooke's law

F = - k y

So,

y2 = 7.51 cm

Thus, the spring is stretches by 7.51 cm.

mass and volume are the answers you are looking for

the answer to this is proletariats.

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