One electron collides elastically with a second electron initially at rest. after the collision, the radii of their trajectories are 1.00 cm and 2.40 cm. the trajectories are perpendicular to a uniform magnetic field of magnitude 0.044 0 t. determine the energy (in kev) of the incident electron.

114.92749 keV

Explanation:

r = Radius of trajectory

m = Mass of electron =

B = Magnetic field = 0.044 T

q = Charge of electron =

The centripetal force and the magnetic forces are conserved

Velocity of first electron

Velocity of second electron

Total kinetic energy is given by

Converting to eV

The energy of incident electron is 114.92749 keV

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f=ma newton

f=100x2.5=250n