5.5 kg of liquid water initially at 12°c is to be heated to 95°c in a teapot equipped with an 800-w electric heating element inside. the specific heat of water can be taken to be 4.18 kj/kg·°c, and the heat loss from the water during heating can be neglected. the time it takes to heat water to the desired temperature is min.

39 min 45 sec.

Explanation:

Empirically, it has been found that the thermal energy needed to raise the temperature of a solid, using only conduction, can be written as follows:

Q = c m ΔT

Power, by definition, is energy delivered in some time t, so we can put the following:

Q = Pt = c m Δt ⇒ t = c m Δt / P

Replacing by the values, we get;

t = 4180 J/kg.ºC . 5.5 Kg. (95º - 12º) / 800 W = 2385 sec.

Converting to minutes, we have t= 39.75 min = 39 min 45 sec.

seeing the graph would

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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