3. a 2kg wooden block whose initial speed is 3 m/s slides on a smooth floor for 2 meters before it comes to a
stop.
a. find the coefficient of friction?
b. how much force would be needed to keep the block moving at a constant speed across the floor?

(a) The coefficient of friction is 0.153.

(b) Force needed to keep the block moving at a constant speed across the floor is 3 N in the direction opposite to that of frictional force.

Explanation:

Given:

Mass of the block is,

Initial speed of the block is,

Displacement of the block is,

Final speed of the block is,

(a)

Using Newton's equations of motion and determining the acceleration of the block:

Therefore, frictional force acts on the block to cause the deceleration of the block.

From Newton's second law, net force  is product of mass and acceleration.

Here, the only force acting along the motion of the block is friction.

So, friction acting on the block is given as:

Negative sign shows the nature of frictional force that it acts opposite to the motion of the block.

Now, magnitude of frictional force is also given as:

where, is the coefficient of friction and is the normal force.

Here, there is no vertical motion. So, normal force is equal to weight of the block.

Therefore, the coefficient of friction is 0.153.

(b)

In order to make the speed as constant, the net acceleration acting on the block must be 0. So, the forward force must be equal to the backward frictional force. Hence,

Therefore, force needed to keep the block moving at a constant speed across the floor is 3 N in the direction opposite to that of frictional force.

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

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