Aknife thrower throws a knife toward a 300-g target that is sliding in her direction at a speed of 2.15 m/s on a horizontal frictionless surface. she throws a 22.5-g knife at the target with a speed of 39.0 m/s. the target is stopped by the impact and the knife passes through the target. determine the speed of the knife after passing through the target.

 = 10.3 m/s

Explanation:

We can solve this exercise using the conservation of the moment; the system is formed by the knife and the target, with an isolated system the moment is conserved during the collision

Knife mass m = 22.5 g and its velocity v₁₀ = 39 m / s, the mass of white is M = 300 gr and its velocity is v₂₀ = -2.15 m / s

Before the crash

     p₀ = m v₁₀ + M v₂₀

After the crash

    = m v₁ₐ + 0

    p₀ =

   m v₁₀ + M v₂₀ = m

     = (m v₁₀ + M v₂₀) / m

Let's calculate

   = (0.0225 39.0 + 0.300 (-2.15)) / 0.0225

   = 10.3 m / s

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j