Abullet of mass m traveling at velocity v0 penetrates a block of wood of mass m and emerges with a velocity v. if the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
express your answer in terms of the given quantities.

Explanation:

As we know that there is no external force on the system of mass of bullet and the block

so we will use momentum conservation for the system

so we have

so we have

so final speed will be

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//