A19.3 kg dog is running northward at 2.98 m/s , while a 6.26 kg cat is running eastward at 3.64 m/s . their 78.7 kg owner has the same momentum as the two pets taken together. you may want to review. find the direction and magnitude of the owner's velocity.

v = 0.78 m/sec at 21.61° towards the east of north

Explanation:

Given a 19.3 kg dog is running northward at 2.98 m/s , while a 6.26 kg cat is running eastward at 3.64 m/s and the mass of the owner is 78.7 kg.

Given m(dog) = 19.3 kg and m(cat) = 6.26 kg

v(dog) = m/sec

v(cat) =   m/sec

Given the

Let the velocity of the owner be

We know that

v=0.78 m/sec

for direction

Tan(α)=

where α is the angle toward east of north.

Tan(α)=

α=21.61°

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.