Asimple pendulum having a length of 2.61 m and a mass of 3.93 kg undergoes simple harmonic motion when given an initial speed of 2.45 m/s at its equilibrium position. determine its period. the acceleration due to gravity is 9.8 m/s 2 . answer in units of s.

T=3.24s

Explanation:

Period of a simple pendulum is given by:

As you can see, it doesn't depend on the mass of the object, nor its speed.

the answer is c.)

explanation:

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.