A300 g glass thermometer initially at 32 ◦c is put into 157 cm3 of hot water at 95 ◦c. find the final temperature of the thermometer, assuming no heat flows to the surroundings. the specific heat of glass is 0.2 cal/g · ◦ c and of water 1 cal/g · ◦ c.

T_f= 77.58° C

Explanation:

from simple calorimetry we can write that

and

Where

Q_w = heat content of water

Q_g= heat content of glass

m_g= mass of glass

m_w= mass of water

T_f= final temp

T_w= temp of water

T_g= temp of glass

m_w =mass of water

m_g=  mass of glass

The specific heat of glass is 0.2 cal/g · ◦ C and of water 1 cal/g · ◦ C.

Now in given case

Q_w+Q_g=0

therefore

+=0

⇒T_f=

putting values we get

T_f=

T_f= 77.58° C

i would say the answer is food.

hope this !