An 8.75 kg point mass and a 14.0 kg point mass are held in place 50.0 cm apart. a particle of mass m is released from a point between the two masses 17.0 cm from the 8.75 kg mass along the lines connecting the two fixed masses.
a. find the magnitude (a) of the acceleration of the particle in m/s^2.
b. find the direction of the acceleration of the particle. either (i) the acceleration of the particle is toward the 8.75kg mass, or (ii) the acceleration of the particle is toward the 14.0kg mass.

Answer

given,

mass of the = m₁ = 8.75 Kg

another mass of the object = m₂ = 14 Kg

distance between them = 50 cm

R₁ = 17 cm

R₂ = 50 -17 = 33 cm

a) Force applied due to the Mass 8.75  in +ve x- direction

Force applied due to mass 14 Kg in -ve x-direction

net force

F = F₁ + F₂

Using newton second law

b) As the acceleration of mass comes out to be  +ve hence, the direction will be toward the mass of 8.75 Kg

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