Warmup: the international space station is orbiting with a velocity of 7,667 m/s at an altitude of 408,000 m. the radius of earth is 6,371,000 m. what is the iss's centripetal acceleration?

is the centripetal acceleration.

Explanation:

As per given values  

Radius of earth (r) = 6371000 m

The "international space station" is orbiting with a velocity (v) = 7667 m/s.

"Centripetal acceleration" is the acceleration is equal to "the square of the velocity" divided by "the radius of the circular path".

V = velocity of the orbit

R = radius of the earth + height of the space station

R = 6,371,000 + 408,000

R = 6779000 m

The direction of the centripetal acceleration is always inwards along the radius vector of the circular motion.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.