Achild sits on a merry‑go‑round that has a diameter of 5.00 m. the child uses her legs to push the merry‑go‑round, making it go from rest to an angular speed of 20.0 rpm in a time of 48.0 s. what is the average angular acceleration of the merry‑go‑round in units of radians per second squared (rad/s2)? = /s2 what is the angular displacement δtheta of the merry‑go‑round, in units of radians (rad), during the time the child pushes the merry‑go‑round? δtheta= what is the maximum tangential speed of the child if she rides on the edge of the platform? =/s

0.043633125 rad/s²

50.26536 radians

10.47195 m/s

Explanation:

t = Time taken = 48 s

= Final angular velocity

= Initial angular velocity = 0

= Angular acceleration

= Angle of rotation

Equation of rotational motion

The average angular acceleration is 0.043633125 rad/s²

The displacement of the merry‑go‑round is 50.26536 radians

Maximum tangential speed is given by

The maximum tangential speed of the child is 10.47195 m/s

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

it doesn't. it was imagined up in the middle ages.