Acube of water 10 cm on a side is placed in a microwave beam having ea = 11 kv/m‘ the microwaves illuminate one faceofthe cube, and the water absorbs 80% of the incident energy, how long will it take to raise the water temperature byso'c? assume that the water has no heal loss during this time.

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

Suppose How long will it take to raise the water temperature by 41°C Assume that the water has no heat loss during this time.

We need to calculate the rate of energy transfer from the beam to the cube

Using formula of rate of energy

Put the value into the formula

We need to calculate the amount of heat

Using formula of heat

Put the value into the formula

We need to calculate the time

Using formula of time

Put the value into the formula

Hence, The time is 133.5 sec.

specific latent heat of fusion, lf, of a substance is defined as the amount of heat required to change a unit mass of the substance from solid to liquid state, without any change in the temperature.

explanation:

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your answer is a “generator”

a generator does not create energy but instead it transforms it.

it’s basically a motor working in reverse.