Arope is vibrating in such a manner that three equal-length segments are found to be vibrating up and down with 321 complete cycles in 20.0 seconds. waves travel at speeds of 26.4 m/s in the rope. what is the length of the rope?

2.48 m is the length of the rope.

Explanation:

Cycle period is 321

Time is 20 second

Wave travels at speeds = 26.4 m/s

We know that,

Frequency required for 321 complete cycle in 20 seconds is

Frequency = 16.05 hz

We know that,

λ = wavelength, the distance between "wave crests" (m)

v = wave velocity, the "speed" that waves are moving in a direction (m/s)

f = frequency, (cycles/ or Hz)

λ = 1.65 m

As per given question "length of the rope has three equal length segment"

Length of the rope = 2.48 m

Therefore, length of the rope is 2.48 m.

f=ma newton

f=100x2.5=250n