You need to use your cell phone, which broadcasts an 833 mhz signal, but you're in an alley between two massive, radio-wave-absorbing buildings that have only a 16 m space between them. what is the angular width, in degrees, of the electromagnetic wave after it emerges?

To solve this problem, the concepts related to single slit diffraction are necessary. The expression for the diffraction minimum in the single slit diffraction is

Where,

d= Slit width

m = Order of the diffraction

\lambda = Wavelength

The wavelength can be calculated through the expression

Where,

c = speed of light

f = Frequency

Note: The angular width of the electromagnetic wave that is width of the central maximum is equal to the twice of the angle of diffraction for the first minimum.

Therefore, applying to our values we have,

To calculate the angle we can use the expression for diffraction and re-arrange for \theta, therefore

The angular widht would be

Therefore the angular width of the electromagnetic wave is

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!