Aladder of length l = 2 m and mass m = 18 kg rests on a floor with coefficient of static friction μs = 0.55. assume the wall is frictionless. 1) what is the normal force the floor exerts on the ladder?

To solve this problem we must resort to the definition of Normal Force, in which, it is the component of a contact force that is perpendicular to the surface that an object contacts.

where,

m=mass

g= Gravitational Acceleration

Normal force that the force exerts on the ladder is the weight of the ladder, then

F=mg

F=18*9.8

F=176.58N

Therefore normal force the floor exerts on the ladder is 176.58N

answer: electrons

explanation:

newton's third law, for every action there is an equal and opposite reaction.