Physics, 21.11.2019 20:31 kajjumiaialome

What is the force per meter on a lightning bolt at the equator that carries 20,000 a perpendicular to earth’s 3.0e−5 t field? (b) what is the direction of the force if the current is straight up and earth’s field direction is due north, parallel to the ground?

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Answer from: wickedskatboarder

To solve this problem it is necessary to apply the concepts related to Magnetic Force.

The magnetic force as magnitude of a vector is described by

$F= IlBsin\theta$

Where,

$\theta =$ Angle between the wire and the magnetic field

L = Length

B = Magnetic Field

I = Current

Since the lightning bolt is perpendicular to the earth then the angle is 90°, moreover we need find the force per meter, then

$\frac{F}{l} = IBsin\theta$

Replacing with our values

$\frac{F}{l} = (20000)(3*10^{-5})sin(90)$

$\frac{F}{l} = 0.6N/m$

Therefore the force per meter on lightning volt is 0.6N/m

Answer from: Quest

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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